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rime-ice/lua/convert_ar_num_to_zh.lua

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--[[
Lua 阿拉伯数字转中文实现 https://blog.csdn.net/lp12345678910/article/details/121396243
--]]
-- 数字转中文:
local numerical_units = {
"",
"",
"",
"",
"",
"",
"",
"",
"亿",
"",
"",
"",
"",
"",
"",
"",
}
local numerical_names = {
"",
"",
"",
"",
"",
"",
"",
"",
"",
"",
}
local function convert_arab_to_chinese(number)
local n_number = tonumber(number)
assert(n_number, "传入参数非正确number类型!")
-- 0 ~ 9
if n_number < 10 then
return numerical_names[n_number + 1]
end
-- 一十九 => 十九
if n_number < 20 then
local digit = string.sub(n_number, 2, 2)
if digit == "0" then
return ""
else
return "" .. numerical_names[digit + 1]
end
end
--[[
1. 最大输入9位
超过9位string的len加2位因为有.0的两位)
零 ~ 九亿九千九百九十九万九千九百九十九
0 ~ 999999999
2. 最大输入14位超过14位会四舍五入
零 ~ 九十九兆九千九百九十九亿九千九百九十九万九千九百九十九万
0 ~ 99999999999999
--]]
local len_max = 9
local len_number = string.len(number)
assert(
len_number > 0 and len_number <= len_max,
"传入参数位数" .. len_number .. "必须在(0, " .. len_max .. "]之间!"
)
-- 01数字转成表结构存储
local numerical_tbl = {}
for i = 1, len_number do
numerical_tbl[i] = tonumber(string.sub(n_number, i, i))
end
local pre_zero = false
local result = ""
for index, digit in ipairs(numerical_tbl) do
local curr_unit = numerical_units[len_number - index + 1]
local curr_name = numerical_names[digit + 1]
if digit == 0 then
if not pre_zero then
result = result .. curr_name
end
pre_zero = true
else
result = result .. curr_name .. curr_unit
pre_zero = false
end
end
result = string.gsub(result, "零+$", "")
return result
end
-- 数字转数位
-- 例如 2026 -> alt_zero ? 二〇二六 : 二零二六
local function convert_digits(number, alt_zero)
local num_str = tostring(number)
local result = {}
for i = 1, #num_str do
local ch = num_str:sub(i, i)
local digit = tonumber(ch)
if digit == 0 then
table.insert(result, alt_zero and "" or "")
else
table.insert(result, numerical_names[digit + 1])
end
end
return table.concat(result)
end
return {
convert = convert_arab_to_chinese,
digits = convert_digits
}